125=100*((9+k/k)^1/2)

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Solution for 125=100*((9+k/k)^1/2) equation: 


D( k )

k = 0

k = 0

k = 0

k in (-oo:0) U (0:+oo)

125 = 100*(((k/k+9)^1)/2) // - 100*(((k/k+9)^1)/2)

125-(100*(((k/k+9)^1)/2)) = 0

125-50*(k/k+9) = 0

125-50*10 = 0

125-50*10 = 0

-375 = 0

-375 = 0

k belongs to the empty set

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